(B^2h^5x)/e^4r=t^3k/y

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Solution for (B^2h^5x)/e^4r=t^3k/y equation: 


D( x )

e^4 = 0

e^4 = 0

e^4 = 0

e^4 = 0

x belongs to the empty set

x in (-oo:+oo)

((B^2*h^5*x)/(e^4))*r = (k*t^3)/y // - (k*t^3)/y

((B^2*h^5*x)/(e^4))*r-((k*t^3)/y) = 0

(1/(e^4))*B^2*h^5*r*x-(k*t^3*y^-1) = 0 // + k*t^3*y^-1

(1/(e^4))*B^2*h^5*r*x = k*t^3*y^-1 // : (1/(e^4))*B^2*h^5*r

x = (k*t^3*y^-1)/((1/(e^4))*B^2*h^5*r)

x = (k*t^3*y^-1)/((B^2*h^5*r)/(e^4))

x = (k*t^3*y^-1)/((B^2*h^5*r)/(e^4))

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